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4 x+ Q+ r7 x( a' M" v通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。' e, t" D9 ]: H
+ ^; i* M7 L( S/ w$ j% G 假设大路开这样的路:
6 J% a; ?( y4 s7 W/ i" t$ c3 E, _+ d& S+ j& G, z7 w
12121212121212121212121212121212。
- B F* s, {( P5 R# G2 m6 Z; k0 M" l
) O1 l b: m% ]3 h6 p 按2珠路,就是BPBPBPBPBP。
5 H3 g6 D- W2 `8 z, O4 X) j
2 D/ w8 Y8 ]1 @# K# ~ 如果我们去掉第一口,就会出现完全相反的结果:
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' V# }" i& g2 l4 f 21212121212121212121212121212121。/ }$ J; \, I @, A% B/ r8 F) {5 O
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变成了PBPBPBPBPB。% ]' ^/ n! \3 y8 R4 f$ P6 M
; Q. J% ]0 D/ G) a8 \
如果我们再去掉一口,又返回第一种情况了。- m/ N# C( q5 ~5 f G# E
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所以每一条大路,按2珠路排列,有2种不同的路数。7 S7 y+ z: e% o2 i& _
~/ @/ m& H( z* w
再举一个列子:4 u4 t9 _- Y- b3 S T/ b8 b
" V# F. i E( e6 _3 n 大路:122122122122122122。9 n: ?. I) L' |
4 c% o/ Y2 N. `, }; [! ~ 按三珠路排列:8 F* b& @1 Z9 g+ k; b% P N
4 \; i. {0 H+ Q7 _ x
122,122,122,122,122,122。
- g1 k; S c* c# i$ P5 x
( k( f$ N8 b7 y+ h# P7 V; g4 L 去掉第一口,变成:8 Z( t% ]5 X3 C7 J5 i+ j8 r! V5 V
% D; ]" Q" R. c# B9 `! d7 o7 ~ 221,221,221,221,221,去掉前2口,变成: E9 o) n( {8 n6 e6 j$ I
( }/ y/ Q U3 P& g
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
$ M/ l" ~0 r( v# C- u# A* b2 R) l
- O# x) a, W) E4 U( |* y: C& q 同理:按N珠路排列,有N种不同的路数。: p' F' `* e0 o/ l1 b. O0 h9 j
. S! p1 i; f6 p" Y. T! l" i( v 我提出这个的意义在于:8 ^$ t1 U$ V* _# w* N
; [$ ^% s: h6 z2 I 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。" y" y/ q1 K1 O' z$ v, Y g
8 m7 X7 P4 q$ z( ]3 P1 L' Y5 O) w
2、为三多理论提供了下注的多面性奠定基础。
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3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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