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( ~+ n# c' K& L1 C' n& D: s" Y
9 T7 R6 q8 r ]6 u2 Z9 a* P& `通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
7 S0 {5 V3 s$ ~$ x: m! c2 D9 z
5 g, Y+ _5 \3 P/ _0 A0 B6 _ 假设大路开这样的路:/ l$ A$ v( N% U" K' Q6 b4 x$ |0 U- s+ N
3 F0 Z/ L- b& d 12121212121212121212121212121212。
+ a I, t- q9 s6 D4 `7 N
; M6 u, [7 F/ _* s 按2珠路,就是BPBPBPBPBP。
2 {* ^+ z. e" F; j& \* W- e7 Z* {; U; G/ n, h8 B
如果我们去掉第一口,就会出现完全相反的结果:
0 F" w; {9 J) b- v6 `; D/ [; b# {! \" m; c
21212121212121212121212121212121。
( D: J+ }1 n' F7 O K0 }1 w: Y# O* T4 s! b9 y
变成了PBPBPBPBPB。5 `1 H6 s5 x% F7 t6 G% w
7 F# N; O. q' P; R
如果我们再去掉一口,又返回第一种情况了。
$ I- Y, }; ]& d% b; v' c2 L8 E$ h. a: k4 |9 Y$ Z- d
所以每一条大路,按2珠路排列,有2种不同的路数。
9 C6 X( F8 {7 p4 C7 N8 R& h m- D& }2 U, }3 _0 l* h3 T+ B" T
再举一个列子:
- i5 _5 s7 |) s `! _0 N
1 H' a4 u" S7 x& C$ p% t 大路:122122122122122122。' B& Q) ~7 ?% F! a! ^
$ [5 X; O" E+ i* z2 S 按三珠路排列:
9 Q9 n2 k# ?& s6 u
5 n8 b. g. `! M) Q2 s" u6 o. j1 e+ m 122,122,122,122,122,122。7 {7 i( H8 ~0 g3 o7 F: s4 ], z, T
1 x, Q) v7 B2 y& P; k 去掉第一口,变成:
3 y) o# h Q- Y4 T& U5 ?! ^
9 a' J9 t' j5 P; T$ _ 221,221,221,221,221,去掉前2口,变成:
* x3 T8 x4 |6 @+ y$ o% W: s0 V$ u1 a$ K2 Z* s
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。9 i9 c+ N4 f& p6 ~( P0 O- ^
, c' [# L% P' [& W# G7 h( _ 同理:按N珠路排列,有N种不同的路数。( _' r+ b( O2 m! E
- a" e' J/ V0 \7 y
我提出这个的意义在于:
4 Q- k$ T" ?. P3 C6 g% W4 z7 [$ G9 o- _: l( g* Q
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。0 l/ N, e( a$ O' t; R k+ n* m
$ `2 W3 F$ E) v7 D/ g1 e' K6 s 2、为三多理论提供了下注的多面性奠定基础。+ P- v" M3 A5 Q" u0 Z
' _3 h. ?6 k2 ]# v" o" b6 q9 J. w4 | 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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