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眼里没有庄闲，只有连和跳，因为庄闲是一对一的，而连跳都是一对二的。理解也好不理解也好，这个讲起来费劲，就不过多讲解了，你只要记住百家le只有连跳没有庄闲就可以了，通常大家所看见的大路，第一行是满的，从第二行开始才有洞出现。( S. S9 o# z$ j' F7 y& Z; S7 ^
z1 X4 ?4 l- n4 ~" T2 A
用什么办法把第二行也变满，让洞出现到第三行去呢？这就需要重新排列大路。一种全新的方式去排列大路（又是新用什么排列，用连，和，跳连就可以比如大路是(随机的）8 W2 w3 n0 ]6 J& U4 `; Q4 M
8 L( N4 U. P1 j/ ]0 s 第一行：OXOXOXOXOXOXOXOXOXOXOXOXOX（第一行永远是单跳）
9 D0 i# u' x4 X! q3 \
+ _2 s6 T4 q$ C1 d) C K1 Q 第二行：O X X O O OX O X （第二行开始出现洞）
1 X$ H/ b# u' l
0 y. x9 R7 s( ?0 W b 第三行：O X O X X( v+ z& ?5 b; |% [! p: d
% ], s# T+ j. D 第四行：O X X
, s& S) y' N% G1 `! P6 p( |" A# p7 p9 }+ W: v% Z% n. |3 k
第五行： X
' n ^# G) u4 A, M: @* y. P/ R8 q6 I7 ^! a: A3 a& |
那么新写出来的大路是怎么样的呢？8 y8 |+ G' e1 x. O
- m3 j: L. G( ]! E4 T
记住一个简单的口诀就可以写出新的大路：1．连是连；2．跳连也是连。# R! p& k9 N2 d( |! W2 ? A, _/ F. P
4 c" W( ^6 s3 p- t- |/ z7 \ B 如下（大家凑合着看吧，实在不行就自己拿笔抄一遍，和上面的路一一对应。）# \" a0 t3 W6 `" G9 N
" W+ O3 k* R$ z |4 d. X: v' ] 第一行：OXXOXOXO OXOOX（第一行不再是单跳了）- A8 q5 a# b& j4 O
1 Z4 j4 I5 g- y o) w3 U
第二行：OOXXXOOX XXXXX （第二行也是全满的）
$ Y' e8 p' W; N' D
+ d4 L" i. i9 i7 D 第三行：OX OX XO XOOX （第三行才出现洞）- r- b7 q b( W! m4 R& g6 ^
+ [' Z" @! _* d" w7 c
第四行：O XO O XXX 8 ?5 Z2 \& U$ J7 m5 q$ k# @" K
: O3 s/ \, i3 w8 N. N 第五行： O
1 ?7 |* \/ l9 w+ ` n
& f; M+ m) D& x 通过以上排列，大家看见了，变换了组合方式以后，大路不再显的那么杂乱无章了。每一列要么是连，要么就是跳连。这就似乎是最初期的关系形态变化组合排列，通过这样的排列，从形态上看，整个路只有12个形态上的跳，其他全是连贯的（可能已经有人开窍了）。0 s2 ], R, A% p# D9 u! t
7 l |) K1 Q: N 大家看第一行不再是完全的单跳，第二行没有洞的出现，第三行才开始出现洞，每一列最少是2个符号，通过这样的形态组合，实际上是减少了原本大路上的跳40%-60%，比如原来一靴牌60把，基本上是30个跳。30个左右连，而且是间隔无规律，杂乱无章的，按常规跳连的次数是基本一致的，周期越大，数字越接近。9 f3 m8 Y: r1 N
$ ?, D0 m9 x; \3 k* h* d5 M 通过配列 可以把原本大路的跳精简到10-15个左右，相反增加了40-60%的连，以上是对大路形态转换的最初级形态，相信已经能对大家有帮助。至于怎么样去下单 ，一目了然了。0 Y( C: b$ L0 e& R
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