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眼里没有庄闲，只有连和跳，因为庄闲是一对一的，而连跳都是一对二的。理解也好不理解也好，这个讲起来费劲，就不过多讲解了，你只要记住百家le只有连跳没有庄闲就可以了，通常大家所看见的大路，第一行是满的，从第二行开始才有洞出现。/ D5 G) ?. Q# V" {3 ]) a+ \' \- v, {
0 t% g5 X) c ^4 n: w7 n 用什么办法把第二行也变满，让洞出现到第三行去呢？这就需要重新排列大路。一种全新的方式去排列大路（又是新用什么排列，用连，和，跳连就可以比如大路是(随机的）1 K* T- k. M0 l+ d2 U
- {/ k" I3 ?! b' v3 M' Y" \7 D
第一行：OXOXOXOXOXOXOXOXOXOXOXOXOX（第一行永远是单跳） n9 F" Z! X- q% P
& |& g5 a6 ^; i: V* T ~! \+ l 第二行：O X X O O OX O X （第二行开始出现洞）2 x# @) p4 {) u/ g
3 N0 X2 _$ r' B& D, C. s) Z! X 第三行：O X O X X
' C2 L6 k! [3 }) K4 q$ _1 y) r1 K0 T8 j# K6 o
第四行：O X X. F+ w" C+ x/ }0 q
' U; [& x0 _( B% T 第五行： X; E+ T- V! U% L- X. L9 `$ h
2 j( m- u* d; }' N 那么新写出来的大路是怎么样的呢？/ {* O f; T6 h9 C& g8 J1 |. i, W i& z0 L
6 Q# n# Z( S$ h6 I L 记住一个简单的口诀就可以写出新的大路：1．连是连；2．跳连也是连。. o8 V+ G% j6 a$ `
3 N% r$ e# T9 R9 R# S4 }9 `
如下（大家凑合着看吧，实在不行就自己拿笔抄一遍，和上面的路一一对应。）8 ~" d5 q; m1 N0 `2 P4 |# `
7 |' m# j/ V7 w- m0 p' L. T$ r
第一行：OXXOXOXO OXOOX（第一行不再是单跳了）
& j/ N/ M: p: f2 q! n
/ o$ q* t2 {9 s 第二行：OOXXXOOX XXXXX （第二行也是全满的）
1 Y, I' I. a' R5 D7 ^/ ]
% ~! }# v' F8 J0 u; i! d 第三行：OX OX XO XOOX （第三行才出现洞）8 I3 w% s3 ?5 L& \" {# R
9 U# W1 M2 K+ q" ]2 N1 _ 第四行：O XO O XXX
8 t9 n* K* F+ f' c0 M& I2 n9 Z! F# H- {2 g2 |; s7 ]& G. x9 m9 H
第五行： O8 v- V' C, h$ N7 F9 t# ]
4 |2 a5 C* ?. \7 m$ k: Y& ]" ` 通过以上排列，大家看见了，变换了组合方式以后，大路不再显的那么杂乱无章了。每一列要么是连，要么就是跳连。这就似乎是最初期的关系形态变化组合排列，通过这样的排列，从形态上看，整个路只有12个形态上的跳，其他全是连贯的（可能已经有人开窍了）。) I, V( }' ~. ~4 F
% j5 @3 ^9 I: M 大家看第一行不再是完全的单跳，第二行没有洞的出现，第三行才开始出现洞，每一列最少是2个符号，通过这样的形态组合，实际上是减少了原本大路上的跳40%-60%，比如原来一靴牌60把，基本上是30个跳。30个左右连，而且是间隔无规律，杂乱无章的，按常规跳连的次数是基本一致的，周期越大，数字越接近。3 N$ R, G1 U$ O7 i3 W" R
: |5 l! P6 N. U8 Y9 r
通过配列 可以把原本大路的跳精简到10-15个左右，相反增加了40-60%的连，以上是对大路形态转换的最初级形态，相信已经能对大家有帮助。至于怎么样去下单 ，一目了然了。
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