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[lastpost] => 2760735 【YZ】8月26日投注流水75095元 1756454320 rainwang
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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。* F1 |5 s7 u9 ]6 @& G+ m. l; ~3 b
# G6 Q/ b' C( z7 I/ ?4 t
假设大路开这样的路:
, h1 K- v; q, v9 X+ v4 s8 p2 z5 u
- Q( Z/ K! i: o8 |" e5 E t 12121212121212121212121212121212。
& H- x1 z2 T& n' Y
3 v4 Z9 B" C" W. D4 M' I 按2珠路,就是BPBPBPBPBP。0 h4 p4 A( q7 o, n n
" ?5 [5 ]# F y& P. S& f, K 如果我们去掉第一口,就会出现完全相反的结果:
3 _) t" `' n! k& u( R* ^9 ?% |4 H r2 j9 s; p" b# v
21212121212121212121212121212121。( ? ]( v% d% D/ s
1 r: t4 t5 |: g 变成了PBPBPBPBPB。
/ i8 Y% g* V; z6 ?6 `3 C2 x' M' z; ? i4 _7 @) b; T& B7 a- n4 }
如果我们再去掉一口,又返回第一种情况了。9 [' B$ J3 m/ J' P) [) q9 ~0 O
. d2 X" c$ Q( e: o8 P: M5 K 所以每一条大路,按2珠路排列,有2种不同的路数。" q: {. H# N, y* S, ?
5 |0 e/ b" b6 S' E. d% M 再举一个列子:
! ]( s4 q, C# w
( r5 v- {/ S7 i/ K" [: g+ G; ?, P 大路:122122122122122122。, q3 \' F! K! _5 @( J/ `
* o0 G. K8 l: h& J; v
按三珠路排列:/ ~% }1 f* T, H2 t: p% C
0 r, X, d$ j5 W& G/ U 122,122,122,122,122,122。
3 b N. v1 S( Z# g, Q
/ K* |2 o2 Z s( `. A1 l% N7 X8 P 去掉第一口,变成:
7 w. X# t: f, K, i1 f9 [$ R/ @ {9 m/ B" [+ z* Y9 j/ G
221,221,221,221,221,去掉前2口,变成: c) _$ R# |5 m# K; E4 q8 y0 @/ |
9 k) P2 b1 N" d* C: T1 ?$ i 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
) W* l+ j2 W. L* t/ E% U) n- k8 [( M4 ~3 F7 A6 |8 m1 s* C* q/ w
同理:按N珠路排列,有N种不同的路数。, p7 n4 Z3 Q- d; w, O
, n- u+ o% m+ j( v; `1 J* j& I' a* l
我提出这个的意义在于:
* H$ t1 }! D' A6 K
9 T( ]3 m% C; K, d" _3 s 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。& d/ n* Z8 t4 j% p7 J; j H
% }! {, {. \+ ]( ~ 2、为三多理论提供了下注的多面性奠定基础。
: K% w5 @! j* w, R7 _- H8 V: S: G. h% T, ~7 P
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
! D: u# v* R& c. {
1 E2 f( i8 E" _* [ } |
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我现在还是研究一下理论打法,感谢你的分享,我也来学习 |
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