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# u) t& T& e/ {! R. t$ q通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
t- \% o, y: V4 d4 s
g: ?% O9 F( ~& e" T 假设大路开这样的路:
7 \( @1 R( D4 T9 N( K4 D7 `0 j2 u! ]; D3 ^* T# l) u, }6 M
12121212121212121212121212121212。3 `$ Z" p" b+ \! [5 D
; W$ A9 s. ]3 o9 b2 G0 W 按2珠路,就是BPBPBPBPBP。6 ]0 Q% S5 W/ M
0 W8 m0 B8 V* D0 [5 I* `7 H( ^$ s
如果我们去掉第一口,就会出现完全相反的结果:3 M& V/ D4 `6 r
) ~; ?8 P+ u" s
21212121212121212121212121212121。
; T4 W. j% k1 d% b
; |/ I7 p6 c/ I) d 变成了PBPBPBPBPB。7 u" P( ~& E2 W% E5 q% X8 I
1 _. d( \4 e0 V c9 B4 `
如果我们再去掉一口,又返回第一种情况了。& c/ E/ c- ^% D: E% \* B3 k% p
5 n0 c" E) j4 n b4 S 所以每一条大路,按2珠路排列,有2种不同的路数。5 ?0 w$ ^$ J4 e9 [2 {* x5 _& }
; N7 s* _( K3 { 再举一个列子:8 B3 n5 C9 t8 y
) C1 u1 l8 T' e; j
大路:122122122122122122。
- ^3 e* K5 t3 g) V6 A8 Z
* E& O% c' M0 \$ Q 按三珠路排列:2 h7 C( E( B8 K* D1 x
4 f/ N2 |; ~, B. R
122,122,122,122,122,122。
& ~3 p( t k/ e9 R# P# n) _7 X8 r, ?7 V+ m6 K" z
去掉第一口,变成:2 T$ Z( `7 e6 a4 H" I
1 m8 L a$ K- T% t8 Q
221,221,221,221,221,去掉前2口,变成:) A( u, D; J/ d0 G7 F C
; b! f, T; b+ V$ @$ o 212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。& ~1 c" U7 H/ ?9 P, G
9 P6 q$ |1 @4 g' g! @4 g 同理:按N珠路排列,有N种不同的路数。
9 Y, ~0 M. w6 U4 g
& U/ E* M7 B- Z d' a 我提出这个的意义在于:
& k6 s/ w8 n! ]7 `2 j; m
9 }% N; q/ m$ t, H, D1 T! v& F 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
7 U3 \% h9 f; V
) z1 u) B' [) s- B 2、为三多理论提供了下注的多面性奠定基础。
, w7 ~# c$ W/ e( s7 q$ W
) O1 i2 }' V* \5 u/ s [9 t# a 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。8 [( R% y8 X- e& y
/ \/ _0 U3 R$ A0 @5 l# U& Q
9 W' k+ B0 e- G& \, z, ]4 A7 w. c/ ~" y* K( G
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