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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。/ X* i! x# z: C4 H( f
6 D7 D$ R, N( i* i 假设大路开这样的路:
, o& ^& I5 M3 J. T W! ^: i; x$ _& e. B; D$ O' q3 K
12121212121212121212121212121212。) [7 V+ W+ ?, h
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按2珠路,就是BPBPBPBPBP。
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) h% `- O o4 N5 X 如果我们去掉第一口,就会出现完全相反的结果:+ |3 G4 w4 o: H5 N E
: ^+ H2 Y5 G1 X* J 21212121212121212121212121212121。/ [; {& g5 b/ Z3 [$ b3 T' M! F
. U3 V" d+ B5 Y8 v5 w) E# `3 @. [
变成了PBPBPBPBPB。' y' i4 O! l$ `8 Z7 e4 a
# I+ E9 t R7 t 如果我们再去掉一口,又返回第一种情况了。- }' E2 F$ v: ]4 c5 l" i5 ^9 `4 N* ^
- R3 [( i) H# }" Q% R7 q 所以每一条大路,按2珠路排列,有2种不同的路数。! `4 M0 U6 ?$ p
5 U; }/ F& m N
再举一个列子:" Q) _2 Y0 a7 q
2 x# H0 s9 x' `* ^
大路:122122122122122122。" ^* d; x; k$ c
( l( D+ ^! o6 w( @9 T1 J2 D 按三珠路排列:
/ w A) }- p* n" u ~: g. u
) F3 {2 \' R0 ~) {. {5 u! B4 f 122,122,122,122,122,122。
; H. B4 ]5 @: E: H5 [
& Y& S& s _ y8 {7 C! _/ J 去掉第一口,变成:
0 F& q" D8 t; I
2 h# R# J5 \& A( a 221,221,221,221,221,去掉前2口,变成:5 b; y! h2 V) v3 h2 P3 d# X
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212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
& \: d3 c9 R5 g: K
4 v! Q. G0 X# Q# z! g- t2 S 同理:按N珠路排列,有N种不同的路数。2 F' V8 }5 O+ P, F' l9 P5 A8 M, ^
/ F7 l) { t; Q5 e# e' T9 ?
我提出这个的意义在于:6 i8 [) c) ~% M* { S4 e% g) z
$ k, v( M$ O5 R3 y1 R- H$ _ 1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。& Q3 ~! L& _: K) v/ I% A( p7 G4 Z
( `* J/ M& q3 Y2 L& [$ ?& D 2、为三多理论提供了下注的多面性奠定基础。. e' ?0 h0 m0 y" l9 M7 g0 \
* ~" M5 Z! X( \: T3 Z! D2 a4 p( ?, \ 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。! o& D# }: F* W8 p5 ^3 E
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