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通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。
+ S L7 d8 f" ^3 e( H6 \0 \0 M+ f/ ?
假设大路开这样的路:
1 I5 A, Z0 o& a) _; `9 {4 C" Y: R, s
12121212121212121212121212121212。
0 _/ i' ]/ l5 x6 q. S% ?* _. }
( c3 \% F0 n4 O( J$ E: \1 t, J3 t 按2珠路,就是BPBPBPBPBP。
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如果我们去掉第一口,就会出现完全相反的结果:
$ l) v3 W, }, H
$ u& x3 W0 E! v! X! b 21212121212121212121212121212121。, b/ U* F: H8 a" P0 v O8 A
5 C' P7 N/ i* t0 {+ J4 M9 A( f( p
变成了PBPBPBPBPB。8 A4 L( R$ `4 ]7 R; q
5 i' P- y2 e& |4 M( N- L* O 如果我们再去掉一口,又返回第一种情况了。
, G G- \5 J. I. d Q6 u
% f: t6 O' j, }( e" \: b, h 所以每一条大路,按2珠路排列,有2种不同的路数。" N$ a. q4 \5 U' r
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再举一个列子:
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大路:122122122122122122。# h3 e8 q7 i8 g; U" ]. w
9 E2 S6 @" f" u0 V& y$ v 按三珠路排列:
. O5 G7 k' [' t2 v2 t( j5 k B
" V P- V# q* P6 H2 o 122,122,122,122,122,122。 I) _; X6 ~" r9 ^7 d( ?1 u
6 D/ M+ t+ |- Q2 `( V
去掉第一口,变成:' Z" J( o7 D4 E: a, K. ?
+ w# i7 B. f# c; w( q5 I- t 221,221,221,221,221,去掉前2口,变成:
. \: y) p( m/ B* K6 v& Z# T* X. E2 V
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。9 p/ w: G! v1 G! M2 d
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同理:按N珠路排列,有N种不同的路数。" Y5 Y! M4 C9 ^ ?1 \' ^$ E; i" i1 ~
6 x3 B+ X! N5 C) l 我提出这个的意义在于:0 E: g8 I* ]( u6 W5 g+ G
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1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
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3 I% I0 o% n) b: h 2、为三多理论提供了下注的多面性奠定基础。# l- H4 L& e' a, K2 \
; u2 t0 m6 W, `; J6 r( c. G& R" T 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。$ v- g& E; p* e8 r: g; }8 V
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