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6 v# u; A" E0 {- I通过我几个月来对珠路理论的研究,发现了一个有趣的现象:每一条大路,按2珠路排列,有2种不同的路数;按3主路排列,有3种不同的路数;按4珠路排列,有4种不同的路数,按N珠路排列,有N种不同的路数何解?我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 G* V' ]/ `3 z+ J5 e
. {8 Z) l# n/ C+ [2 E 假设大路开这样的路:, |8 h: y5 @3 r! ~3 v: G
. G. [# D* d" j 12121212121212121212121212121212。
- S: o2 F7 g+ a- ^
& J' p+ w5 v. G. Q/ K$ o6 ]6 E 按2珠路,就是BPBPBPBPBP。7 C# ?4 G- z5 q2 o b
8 m1 O& I! m" Y9 b. y1 r' f 如果我们去掉第一口,就会出现完全相反的结果:
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8 X; n3 I: A& S! p5 \2 }; U9 v* i 21212121212121212121212121212121。
5 e! x+ a2 N" o6 {! ?: v
' J7 S, U- f2 F) {+ T; c2 g 变成了PBPBPBPBPB。
" x& B2 x( o, U* D. n9 F# n2 J$ O4 X
如果我们再去掉一口,又返回第一种情况了。. C+ _7 }! q' @( c7 {
: P0 q* [7 ~1 k( k2 G" s' a 所以每一条大路,按2珠路排列,有2种不同的路数。
5 n7 G* m; K/ b" f
1 z2 s8 ~, m) G+ a8 @( M 再举一个列子:2 k4 J; i3 b+ g9 N7 r O
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大路:122122122122122122。$ e2 K7 ^) D% u! z" {
/ [! Y4 U: p7 V3 b2 d9 ?2 J& z 按三珠路排列:' B5 ^2 W) d5 t
0 \4 A2 B4 W' G! R
122,122,122,122,122,122。
' S7 ]& R( R7 M% n+ x E. f
0 F, `+ G( f- k$ i( o1 d* R 去掉第一口,变成:1 F& } R2 x) m5 c; r- o9 N
! U: A- J0 o1 j) ?+ N9 P3 N
221,221,221,221,221,去掉前2口,变成:% C) y, r) f$ V4 g
2 i# x& N& q5 ^+ |
212,212,212,212,212,去掉3口,又返回122,122,122,了所以每一条大路,按3珠路排列,有3种不同的路数。
6 @ n4 a( F, S! A/ R. e' p* O
* P3 y, n6 L: D$ t 同理:按N珠路排列,有N种不同的路数。
6 E1 d) Z# S, w' [3 E% a
5 y" W: Z- J' o$ r% @* F. p2 _ 我提出这个的意义在于:
& d; z* ?' v$ k# c; H: C# [- {* h- E% F, w8 S
1、字串81、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。 ^2 j. [: H0 V- `
# i0 v9 [# V9 }8 G8 Q! F+ q 2、为三多理论提供了下注的多面性奠定基础。6 v" b: Y3 q; P- W. C# }6 m
6 m+ A: W4 y1 m3 d! P) f 3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是上上路。
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