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眼里没有庄闲，只有连和跳，因为庄闲是一对一的，而连跳都是一对二的。理解也好不理解也好，这个讲起来费劲，就不过多讲解了，你只要记住百家le只有连跳没有庄闲就可以了，通常大家所看见的大路，第一行是满的，从第二行开始才有洞出现。6 d v R9 }! C, O0 B0 L6 }1 {' q8 e
7 B2 p# \0 _+ n. v# T2 n
用什么办法把第二行也变满，让洞出现到第三行去呢？这就需要重新排列大路。一种全新的方式去排列大路（又是新用什么排列，用连，和，跳连就可以比如大路是(随机的） v/ a8 h9 D, o, ?2 [, m; c+ M
7 p/ W6 j0 ^7 Y( r9 { 第一行：OXOXOXOXOXOXOXOXOXOXOXOXOX（第一行永远是单跳）
3 e0 r6 ^+ Q8 q8 h/ {- F3 `
# ~! t4 O0 o! i4 y, d& N9 p2 m 第二行：O X X O O OX O X （第二行开始出现洞）. H' r8 e9 T0 t1 w0 V7 b; O
5 N1 s3 h! G8 Y1 V0 `
第三行：O X O X X' H! B/ Q, l& L2 Y2 Y/ \- o ]7 W6 o
. {. u# Q6 U) g J4 O: R1 R2 I 第四行：O X X& F6 L C9 u. m- [; w2 o& m$ r
" ?; ?2 N4 w2 E$ o% Q; a 第五行： X
2 i, f) n7 ]$ B6 @- _: A0 o% [, H- k
那么新写出来的大路是怎么样的呢？ K5 n" D: X9 t5 k v: D! y
) C/ a: y$ h9 o9 r* H
记住一个简单的口诀就可以写出新的大路：1．连是连；2．跳连也是连。
/ R: a }4 s6 Q" R* o. \
# z0 O, _/ N* L! R' g 如下（大家凑合着看吧，实在不行就自己拿笔抄一遍，和上面的路一一对应。）& b0 }& Q3 N) }8 R
/ y v" u2 C- ]) G/ s) a
第一行：OXXOXOXO OXOOX（第一行不再是单跳了）. H: S% L, f! H, S) z& y# S2 y$ i) o
1 @& M8 `* u: l- C, N$ w 第二行：OOXXXOOX XXXXX （第二行也是全满的）
. c3 A4 i, s& L. m
3 e$ Z6 w: p# R 第三行：OX OX XO XOOX （第三行才出现洞）
' b% ~! M+ ]2 B# ~0 ` A6 W, q
+ h$ y+ Q9 ~( R. J 第四行：O XO O XXX
$ P$ p5 \9 B& o$ d" [9 C% Q
& d' ^9 j! d+ r. n 第五行： O
% [: \# q( a% Q+ v+ j6 E
. n/ F8 ^1 N( V0 M3 ? 通过以上排列，大家看见了，变换了组合方式以后，大路不再显的那么杂乱无章了。每一列要么是连，要么就是跳连。这就似乎是最初期的关系形态变化组合排列，通过这样的排列，从形态上看，整个路只有12个形态上的跳，其他全是连贯的（可能已经有人开窍了）。& |0 q. W* C2 k
: E8 o8 r/ O) O 大家看第一行不再是完全的单跳，第二行没有洞的出现，第三行才开始出现洞，每一列最少是2个符号，通过这样的形态组合，实际上是减少了原本大路上的跳40%-60%，比如原来一靴牌60把，基本上是30个跳。30个左右连，而且是间隔无规律，杂乱无章的，按常规跳连的次数是基本一致的，周期越大，数字越接近。6 ^& k0 w/ K7 ?8 U& T# J
0 M( y: C; V; f3 C9 u. ?* A0 p 通过配列 可以把原本大路的跳精简到10-15个左右，相反增加了40-60%的连，以上是对大路形态转换的最初级形态，相信已经能对大家有帮助。至于怎么样去下单 ，一目了然了。9 o D9 s" B. }' W0 E$ x
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