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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O4 X1 n! L$ v$ F* T. |7 J0 ?
7 F" M) G/ X3 t N( H0 D% w发现了一个有趣的现象,3 K, E. y6 ~+ r
每一条大路,% c. @( F2 n" Q3 u) {
按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f) A- N4 e' O F: e
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
( q1 S' U3 m! I' b, ?按4珠路排列,有4种不同的路数3 u, T0 I' q c8 [: ~% r" Y
按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C' a+ h% t7 ]( O! @7 n
什么意思呢,可能大家一时不清楚,9 Y* q. t* q/ r3 |* q, T! V
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l, R8 p6 y4 q ?5 n8 j1 ^
假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u
8 \* U: @& s% c% {$ T; z: e12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h3 |6 a R( w( w4 z- C) p$ N/ `
够极端了吧
6 y& z) M# i( \; H( ^; ]按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
: k8 j3 J& a- n8 d4 J" ?/ O如果我们去掉第一口,就会出现完全相反的结果:
8 v. u, ?- |, V1 {1 a7 g& f212121212121212121212121212121215 r0 Q& f. D" u- T( [! r2 M1 Y. J
变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C6 J" m7 ?( z% M3 _& O9 `
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O8 Z( f- h; n% D5 ]6 [# m
所以每一条大路,! R6 V# q$ h. c; z% O
' N. l" N+ k( n9 A9 J9 \按2珠路排列,有2种不同的路数。
9 a; f7 y) q* m' ]再举一个列子:! H8 v3 H J0 {: S9 P% y2 E
大路:122122122122122122。。。! I- ~/ W0 l. ]5 Q8 N
按三珠路排列:! a( y- q& I6 C7 B0 z
122,122,122,122,122,122。。。7 J0 W9 v# y2 O& x" `6 k7 T
去掉第一口,变成:6 G2 V! \" L' c" k: d# c6 j6 n/ H9 s E3 f
221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M3 n. }: n A) y7 l" l7 {! m
去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W
& b u2 ^( C; h5 E- m) o212,212,212,212,212,: y& l, B; I6 e- m. J# c) `* V8 z& x% i4 C7 u/ X
去掉3口,又返回122,122,122,了" k1 B' z8 p W, W1 c
所以每一条大路,
# h1 B) _' g" I) R' T按3珠路排列,有3种不同的路数。1 E/ [$ H6 {: \4 [7 @; ~
同理:按N珠路排列,有N种不同的路数。
$ K% V. g' U& n" u- ]9 u& ~我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
% K) r+ r7 c# u字串83 L: R) G1 V- s2 Y+ Y. `5 z8 j. N8 O. [4 C: _' B U
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
7 L& l( P, e6 a& T7 C. j2 O1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
4 i* ?- g3 b0 K& v8 M% H7 S1 V2、为三多理论提供了下注的多面性奠定基础。% |" J+ B: P& K) t- p
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.* `) L. V7 Y% X
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