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通过我几个月来对珠路理论的研究,0 Q8 F1 c7 c, g$ u: c, g
; k9 D9 `: S: q5 r+ Y# _* E+ _发现了一个有趣的现象," j# P" |' b9 O( Z% x; T& K
每一条大路,
( G; [% H( {- |按2珠路排列,有2种不同的路数, x5 t+ p; i( [/ M5 l0 a$ e
按3主路排列,有3种不同的路数) k7 b$ Z- G7 ~. H2 f; `% K; ^# Q
按4珠路排列,有4种不同的路数# t$ }. m$ s% \* B1 ~7 |0 v- F+ c
按N珠路排列,有N种不同的路数。9 r8 C: A$ U, p7 B
什么意思呢,可能大家一时不清楚,
N5 i- A, [/ Z3 N我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。4 b j+ m4 U4 g( T; U- c
假设大路开这样的路:
: T& ]6 @# M) f- Y- n- D12121212121212121212121212121212
( C ^, L5 [# O" W! X够极端了吧5 S) i8 t; K( l( v$ T% f
按2珠路,就是BPBPBPBPBP.....( R* w% g u0 ~5 p6 d7 r3 G
如果我们去掉第一口,就会出现完全相反的结果:/ ?' B6 @7 c2 g8 @5 v$ z+ J4 v7 g
21212121212121212121212121212121
* M8 y" B2 f0 S# ?4 v- G1 }+ w变成了PBPBPBPBPB.......1 [7 h& {3 ^( K) L* X9 a V
如果我们再去掉一口,又返回第一种情况了。; r1 T+ \( c5 |- b
所以每一条大路,
; R# V# \( v+ e7 l按2珠路排列,有2种不同的路数。
3 z" l9 V c+ s再举一个列子:
5 E4 I* h1 V% W8 M9 a1 R3 _7 P( z大路:122122122122122122。。。& {9 m* M7 b7 m: W8 O6 H% o
按三珠路排列:( I; D9 E+ Q% f, O
122,122,122,122,122,122。。。
% B3 ~4 F- z l7 J7 h3 D% u, P去掉第一口,变成:
* r. h/ j+ ?4 j7 |* i; \# q# U2 [221,221,221,221,221,
. |; y: v; u4 c J: i) x+ n去掉前2口,变成:
8 ^! G$ R7 Q& Q212,212,212,212,212,/ r7 Y: A }6 A2 l& d
去掉3口,又返回122,122,122,了% x! [0 O& O* Q
所以每一条大路,
g* K- G! H; a+ Z: {按3珠路排列,有3种不同的路数。# L8 F" z8 Z9 C! k
同理:按N珠路排列,有N种不同的路数。
* Q& G) q G( k1 j我提出这个的意义在于:
9 a0 C) {2 {! n字串8
9 C5 |. H$ o0 h3 y W, T: y3 @5 t( B% |! T
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
$ y- k' R5 v, L" ~, K W2、为三多理论提供了下注的多面性奠定基础。* w* b' i2 {) B% ]# }% A6 f4 K5 G! Z
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.9 T- @1 E2 i! l1 y" H+ k
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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