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本帖最后由 版主05 于 2013-5-1 13:24 编辑
9 |* O$ P3 ] D* H2 t' b2 o0 N! c6 b6 l- `% v
BBB PPP 为1式
* a1 b i! q' X: O( x; W& c+ iBBP PPB 为2式; k `' L# F. E' I
BPP PBB 为3式
8 T' O* B4 B# a6 A/ kBPB PBP 为4式。; }; V) p4 _5 u& r5 U; f) w
" ]3 A: w4 D1 f1 S3 M观察前三列三株路, 共有三种情况,
- _$ N7 l: X3 e, s$ w+ W# n! `* I/ Y: E0 l
6 f8 Z( j3 s0 l5 a0 k: F0 q2 i* }
1: 三列三株完全不同,即存在盲门。 从第4列开始打盲门不出。 直到盲门出现, 在此过程中, 除最后两注连输外,其它都为正值。
" c; t2 \2 Z8 X, H/ c8 ?, C @, b2 k2 l7 d- S6 i) F
; ?0 _( M2 w+ u8 E
BPPBPBBBPB; d& M, v6 L" w
BPBBPPPBPP
0 L0 i- L: h# V+ a9 U4 q BBPPPBBPBP
, R, P) T+ k) Z/ B/ q* N8 [" J; y 12421421236 I" j: T) ]# N
/ }( T! C- Y# u' I6 ~ H
前三列为124,3号为盲门, 从第四列开始打盲门3号不出,直到打到盲门出来, 遂放弃此靴牌。& ~. X8 G! \8 H
+ {$ j+ F' K1 |7 m2 K! R+ B: F- T2:三列三株其中两列相同,举例:
+ T% n T: S8 u1 b5 m4 w' b BBPBPBBPPPB( {9 f% T1 u% I _ n
BPBBBBBPBBP7 v" Q: d9 l4 {9 R* W; z
PPBPBBBBBBB: {7 i9 r" A" [) f
23323112334# N6 T$ `1 j; U
) v+ Y9 ?% y, V& Q0 v 前三列,有两个3式:BPP PBB,一个2式BBP,从第四列开始投注非2式即3式, 如第四列前二株为BB,第三手即打2式的P,直到打到出现第三种不同的三株,在此例中为1式,然后接着打盲门不出,此例中盲门为4号,, d$ A+ T+ t" [/ {/ U
' \" p) { q5 e0 N
3:三列三株完全相同,(较少见),你可以选择等待另外一式的出现,心急者可以打出现的这种三株。其后跟上面两例相同。不再举例。
5 R# [ {9 O- H4 H! n& D+ C1 D1 G* J$ i
有点:充分利用三株路串联的现象,减少连错情况发生。 |
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回复 1# 有一天
. d9 O& q4 X8 c; D" z* `: {& c* v
, L* ~7 |& M; c& i" w* m" _5 Q$ h5 Q" u, t% ^. E
弱弱的问下什么是三株路, 老实说真不知道什么是三株路:) |
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