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通过我几个月来对珠路理论的研究,5 R+ y* d$ ? k6 I7 G/ O
; r% Q( A1 u& y7 U7 ^( d# ? @2 d$ K& k) [/ `6 M
发现了一个有趣的现象,
) h% G2 I! Q7 q5 t, R每一条大路,' T$ B) r% k" [' k
按2珠路排列,有2种不同的路数1 _% l2 j Y8 @" u) {# f
: G- m5 z. y+ k U3 c按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
* }( g3 R; E F# G `按4珠路排列,有4种不同的路数3 P7 O7 `7 H, W8 j7 C) U
按N珠路排列,有N种不同的路数。: n1 f3 R9 @ p% ]* C
+ q# R5 i7 }9 | u9 W8 E什么意思呢,可能大家一时不清楚,
* f9 D) ~) `' P; Z1 M* p我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l7 L: z2 s. ^! Y5 W, e
假设大路开这样的路:! z ~0 G3 v. K' o5 A4 ]" }5 w# u0 o- u; V' T9 c! P3 `" d
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h: K0 F/ ^9 i$ R8 X6 p: a" Y% B7 |
够极端了吧
* R. t- Z; V2 c o1 s9 T按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
, O; R* h1 S* C1 O$ M, @如果我们去掉第一口,就会出现完全相反的结果:+ f$ }+ ]2 l. w" ]
21212121212121212121212121212121
) X9 C% L8 g: M5 g Y3 n变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C& N0 ~ D- z' n7 H, u' @9 _$ o
如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O; S/ m! j' D( s
所以每一条大路,! R6 V# q$ h. c; z% O2 F w/ l: i& p- k |( x, `
按2珠路排列,有2种不同的路数。 Y* j; t% C# e' l* o
再举一个列子:+ L& r9 n3 G. Q( v; O7 R7 v) X
大路:122122122122122122。。。3 G2 T) z8 {6 J+ U
按三珠路排列:, [) O' }" p# w
122,122,122,122,122,122。。。/ [: c8 c# w% v! d% ]" V: l4 H
去掉第一口,变成:6 G2 V! \" L' c" k: d
- [! m% q- M2 d- U5 P6 W- M& f+ M) g221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M
, n H9 M% f6 B( _( p去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W
- e0 |4 J6 I5 t212,212,212,212,212,: y& l, B; I6 e- m. J# c) ` D2 K6 O+ {0 S5 j. h5 M6 s0 ]
去掉3口,又返回122,122,122,了
' `' d- V6 W( F: p3 f% T$ i所以每一条大路,7 C& `* C" S) b
按3珠路排列,有3种不同的路数。# n3 p- k2 w# r, v2 Z) b
同理:按N珠路排列,有N种不同的路数。
' v2 j+ c% T- S+ o: W9 F% \: Y我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
* Y( w/ z$ Q% H4 O5 S7 Z$ G字串83 L: R) G1 V- s2 Y+ Y" N7 ?3 s+ H9 N4 F, L& r; H- z" Z
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @
; b+ j- J" F8 `* ~" w1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
: U" t; _% F2 f3 X3 m# @2、为三多理论提供了下注的多面性奠定基础。
& ?5 P4 ^2 o9 H* Q+ ^) m3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.
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