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[打法交流] 德州扑克手牌组合有多少种?(转载)
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1#
起手牌组合% M, X8 _, _: j5 D" \9 |  B
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德州扑克中可能的手牌组合数有C254=(54*53)/(2*1)=1326种特定的对子牌有C24=(4*3)/(2*1)=6种组合" u( f9 ^6 @" }1 ~$ R
特定的非对子牌有4*4=16种组合8 G, `) K1 v; u$ X1 F: W# M7 U+ ^

, s" b: t- \/ G2 g5 o. z+ \7 J特定的同花非对子牌有4*1=4种组合
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AXs有13-1=12种组合! I2 p& `' ?# I# @0 G2 v
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KXs有13-2=11种组合
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  Z7 q9 T, B9 Y7 J3 A' [( _" m思考:去牌效应的应用。
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5 M' X* m7 n. m; THERO手上有一张A,那么对手AA的组合还有多少呢?
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; }( Z# M) |8 b/ n' G答:有C23=(3*2)/(2*1)=3种,与你没有A时的情况相比少了一半。6 n# N3 A+ b. M" K, M) f/ q
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HERO手上有一张A,那么对手AK的组合还有多少呢?
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: {6 ^, M( y5 X/ o答:有3*4=12种,与你没有A时的情况相比少了1/4。; j6 _& u1 a8 g3 X% w2 v0 b  X
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手牌组合
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成牌组合  p6 }! a+ g: r4 U% v7 h8 V3 u
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FLOP没有公对时:  h5 k/ w& J& \
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三条的组合有C23*C23=9种
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指定三条的组合有C23=3种3 I  t- J0 J9 C  v6 r) M

* k4 K2 }: o% Q5 r* M! |两对的组合有C23*C23*C23=27种. M' T" n. }  S8 x- L

: g, Z9 P3 P- y9 J指定两对组合有C23*C23=9种
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TPTK的组合有3*4=12种9 `0 X: L, ]; V( d
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! L0 ^& z$ ]  w, e- V% o: l6 QFlop有公对时:
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明三条顶踢脚的组合有2*4=8种2 B9 O1 e$ x  |9 q
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葫芦的组合有C23+C13*C12=9种
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听牌组合
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; c$ E# [' ?; g4 w4 X: U8 iFLOP有两张同花时:
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/ M$ u& L1 J4 a2 E对手理论上的同花组合有C211=55种
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而当你手上有一张同花时,对手理论上的同花组合有C210=45种
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$ Y' A! N# y1 C) A% z+ P9 j在类似K34这样的FLOP时:
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2 ~8 P/ ?/ S% z; ]/ N5 C4 s两头顺组合(25、56)有2*4*4=32种  \9 Y& x9 V: C% n- t/ o

! ~+ V/ z+ L4 ?( g% a; Y: a0 O卡顺组合有(A2、26、57)3*4*4=48种
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; j6 w: I/ a+ Y4 c在类似K56这样的FLOP时:, d, @0 m+ ~. ]: `' j1 c
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两头顺组合有(34、47、78)3*4*4=48种2 b6 f$ L( z8 Q" m, x6 f

4 o7 c. p2 P) A( T: H$ T9 w! U卡顺组合有(24、37、48、79)4*4*4=64种$ Z6 B( P$ o+ G) ~5 R% \- Q; N% z
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思考:当你知道对手只玩同花连牌时,组合数会发生怎样的变化呢?(这个请大家自己做个计算吧~)
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avatar 天策-瑶娥 + 3 理论区转载发帖奖励

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2#
这个组合应该是很多的了啊。
avatar
这个组合也是要看一下的了
avatar
4#
知道有多少种,肯定是有好处的
avatar
5#
主题回复处广告图案-天策传媒
你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了
avatar
6#
感谢楼主的理论分享,也是可以了解到好多的。
avatar
理论实践得好,收米的时机就来了。
avatar
你估计也是一个理论很内行的玩家,感激楼主的分享。
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9#
老哥的理论打法也是有在记录中的呀?
avatar
10#
这个理论打法是需要向这个朋友多学习一下的。
avatar
11#
基本理论也是要学学的了哦
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我的成果的功劳都是楼主像这样的理论分享。
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理论也许看着很牛逼,但是我还是不行
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这样的理论还是需要多多看看一下。
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这样的理论打法是十分科学好有道理哦,我也来收藏
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16#
老哥的理论打法还是很好啊,来收藏下了解下了
avatar
理论看看一下,肯定都是不会吃亏的。
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