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如果双色球使用10+4复式投注需要投注金额1260元,如果15+6复式投注要几万元,对一般的彩民而言,进行长期这样投注通常不可取。- s! ^4 \5 {# i0 V5 O3 c
考虑双色球复式投注需要很大的投资资本和市场风险,笔者推荐一种组号方法——旋转矩阵10+4的复式投注!既能节省投注资金又能确保中奖率!% x9 R- T. x0 [ |4 @, u
旋转矩阵10+4投注公式
" e4 x0 T* s3 g. _ 旋转矩阵10+4作为复式组号投注双色球,即选出红球10个号码:A B C D E F G H I J;蓝号4个:WXYZ,那么它们通过旋转矩阵公式为:1、 ABEFGH + WXYZ
. i- ?/ I0 x' w/ U- v/ k2 Q9 W' k4 K 2、 BDEFGJ + WXYZ
8 E! l+ E" r! i, t3 W 3、 CEFGIJ + WXYZ- e" C; x6 e( n3 M9 R! W0 K
4、 ABCEFI + WXYZ9 [) j. v3 _6 o
5、 DEFHIJ + WXYZ! x1 Q4 L3 l9 l: O, ^1 l$ h( ^
6、 ACDFHJ + WXYZ
. h% e% q! ?: M# Q$ w 7、 ACDEHI + WXYZ
7 [$ h) W5 g( L9 ]2 T2 T. K 8、 BCDEHJ + WXYZ
0 O( j3 J) t, I5 P3 d. M 9、 ACDFGH + WXYZ
' n4 p" ?: D9 e1 j6 G 10、 ABDFGI + WXYZ) i; d. z# y' ^5 K
11、 ABCFHJ + WXYZ
) {/ b# n. w+ \# c5 ? 12、 ABGHIJ + WXYZ
5 a' J$ W) k7 ~* @" N7 y 13、 BCDGHI + WXYZ* i" p0 f& k4 ^$ S
14、 ABCDIJ + WXYZ
% h C$ p5 Y4 ^) h( ~ 模拟投注:- C: R W. [1 R! o: Q( G* Z1 X
如果将预先选定的红球为A:02; B: 03; C: 08 D:12; E: 15; F: 17; G: 19; H: 25; I: 30; J: 31;蓝球为W:03 X:06 Y:12 Z:13.代入上述的旋转矩阵,就可以组合出以下投注号码:4 F o+ f! i, q
1. 02、03、15、17、19、25 +03、06、12、130 ~1 q- o) F, [( I
2. 03、12、15、17、19、31 +03、06、12、139 W! {+ D Y0 f3 {
3. 08、15、17、19、30、31 +03、06、12、136 [3 J3 y8 {+ N- f
4. 02、03、08、15、17、30 +03、06、12、13/ V' _% |* G4 s2 n
5. 12、15、17、25、30、31 +03、06、12、13
5 X) T9 S4 [, I+ u2 D* o 6. 02、08、12、15、25、31 +03、06、12、13
6 i4 A0 D+ y3 n* J1 e$ g 7. 02、08、12、15、25、30 +03、06、12、13
" `3 x1 a- Y! O0 `% q 8. 03、08、12、15、25、31 +03、06、12、131 N9 g, J N Y7 q
9. 02、08、12、17、19、25 +03、06、12、13/ K6 X& P1 U3 q
10. 02、03、12、17、19、30 +03、06、12、13
" R& p* P& ^. r$ X 11. 02、03、08、17、19、31 +03、06、12、13
8 X8 U8 F r( P; a- }4 T ~ 12. 02、03、19、25、30、31 +03、06、12、13
8 R. T* T% @0 k- M9 }& g9 s 13. 03、08、12、19、25、30 +03、06、12、132 ]' x7 h: y: ]5 Z& B
14. 02、03、08、12、30、31 +03、06、12、13' i* }5 h j1 D& W
由此可见,用10+4复式投注需要投注金额1260元,运用旋转矩阵10+4的复式仅需112元投注,即旋转矩阵组合出14组6+4的单式投注,每组8元,14组只要112元。假如10+4个号码框中了开奖号码的6+1个,那么这14注当中至少有1注中三等奖,假如运气好很有可能中6+0甚至6+1的机会。从10+4复式投注金额1260元到旋转矩阵的112元,从中节省了90%的投资资本,达到中奖和省钱的目的! |
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