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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。
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& {# ?( h1 b2 j7 f1 z一般来说,
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二连赢的概率是25%6 y& }) C* N# d! N, X2 a2 O4 w
- O/ i0 _1 K7 N4 R% Y9 @' ^三连赢的概率是12.5%; V9 y3 Y6 p( [/ E
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四连赢的概率是6.25%% V5 k2 p* {" m3 e
# J* l+ h4 o7 Z% H# V" I……8 ]- X9 M) y5 h
! k8 g7 p0 o4 }0 |) b Q十连赢的概率是0.09765625%4 l% V4 D: h6 \
8 {' V" q7 Z4 e. p; i这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。
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4 V8 q% j( A }$ p百家乐的真实概率含义是:
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8 S) b& h- f1 A9 H假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球! g' A) D/ `) v x8 R
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1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。$ q8 V. n3 b& U$ ]" g. p* l
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你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
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) v1 k7 D# D5 s6 {! T2 ]" }7 }" S另外一个说法是,
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: c3 U0 `# } ~) N9 I& T1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。& |- W, a8 F; p: e
' r/ K9 f# r+ F4 b& S5 j# G1 k再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。! m# p4 A" m3 [+ d4 C, x
* G) _. ~8 |9 C; h平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。4 ^+ c1 T% X- f1 f
7 X' W# y8 s. u- d9 r3 t$ L对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。 P$ y/ q3 T2 _
, D8 T0 c' V6 H e, j举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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第三,凯利公式的问题在于:形而上学。/ T2 D; y' h; Y% Z, D( U2 \
8 B5 R0 n% \% X& K8 S首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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事实上,你玩的时候,基本上每次都能打到。# r. R" ~% l; E% e& k
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因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。6 e: u0 i( r/ w4 J& V
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