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福彩3d两码合的专题研究1、两码合只有2种形态:两奇一偶,全偶,没有第三种情况。
! q+ D6 ~/ f B( m2、在两种形态中,两码合两奇一偶选出的奖号理论概率为75%,两码合全偶选出的奖号为全奇或全偶及豹子。理论概率为25%。6 K) W6 z. U, n( F
3、开奖号期期必定出现两码合偶数,也就是只要有把握分析出每期两码合中02468出哪个就可以直接下注。也就是你说的5选1,每一种均为60注号码(含2注豹子及全奇全偶)。直选则为272注。原则上选好一个偶数合不进行杀号排除,因为此时的注数即可达到赢利。
g$ s' C, \( X; X# A) H1 p7 }: H4、在两码合中选择一个好一个偶合,配一个奇合,为组选10注,其中无全奇全偶的号码,10注号码含组三组六,不含豹子。6 T1 w8 z h9 }) E [" y. O
5、全奇全偶类型,即在两码合中的偶数合(02468)中进行5选3。也可定一个两码合胆,再与其他数字搭配,如定胆4,则为40 42 46 48,去重号共计32注(含组三组六)。
3 _& @" k J4 C# V3 [3 ]3 k两码合偶合:
- q; W! ]* { [7 M9 L/ \5 R$ [0=00 55 19 28 37 463 ]: V3 v& P7 n2 j6 Q/ B Q9 X
2=11 66 02 39 48 579 X0 w, q1 J6 k2 a+ }: M
4=22 77 04 13 59 68
E0 k% k* v9 N6=33 88 06 15 24 79 y0 d4 n6 o8 R2 a' p" Q J
8=44 99 08 17 26 35' ?/ K: u1 O* H1 w
每一组各6个2码,总计为30组,无论1000注奖号开出什么,必定在5组其中开出1组到3组(开出1组偶合表示奖号为两奇一偶或两偶一奇,开出3组即表示奖号为全奇或全偶及豹子)每期选号可以从这个2码大底选取一组2码直接组号选号,或者通过排除多组2码,将剩余2-3组2码组成大底加如其他条件缩水后选号。9 y! H* `9 r) W- q1 @3 ^* j- F
举例:( L/ J- z1 V9 d. { H
一、两码合只出现一个偶合,其他2个必定为奇合
) |" g, _4 p# U3 G奖号:615,两码合为761,其中偶合6出现,只出现一个偶合,对应的奖号为两奇一偶形态。
: O8 \0 d: N) u9 V) B O
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你的理论打法不错的呀,赢钱了应该是打法对你有用哦~来收藏下了解下了 |
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我现在还是研究一下理论打法,感激你的分享,我也来学习 |
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