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[打法交流] 百家乐必胜法理论探讨:只谈理论 不谈经验(转)
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1#

" y8 V4 ]) _5 g9 x' q8 B理论是很简单的,没有超越传统的数学概念。7 ~* U0 x* g6 ~# m! L

" \( x& N' d; V1 a用一条负追的1,2缆,首先下一个基本码,输了下两个基本码,连输两次就是断缆了。2 b3 G( `& Y! m8 U
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接下来把这条1,2缆分为两个部分。. r9 ~- _( U  J* Z3 O

' b. [! U1 M' e第一部分是连续赢了两个基本码,发生的概率是:. u( F4 N7 l2 X0 p% ]4 {; M
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(+ + )1/4 (+-+)1/8 (-++)1/8 (-+-+)1/16
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1/4+1/8+1/8+1/16=9/16* c/ u/ {1 l- }  T# M8 S5 m
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第二部分是在没有连续赢到两个基本码后就断缆了,
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$ R8 U) w$ H" t3 q0 Z发生的概率是:(- -) 1/4 (-+–)1/16 ( +–)1/8; J" V" I* y! O% b9 R

  h! y% S9 T( g. ]2 s! `& _) j1/4+1/16+1/8=7/163 O  V: i7 m0 a* u# ~5 F

  P# A( [; N$ A& u这样第一部分发生的概率大于第二部分发生的概率,也就是连续赢两个基本码的概率大于在没有连续赢到两个基本码后就断缆的概率。" u3 c% L5 b7 g6 n. }- [- `
0 [! {1 i" c5 i- c# y- O# U# M: c
9/16大于7/167 x3 u. q8 C7 D% K( F

5 E; ]# z: k, P1 j0 U' J来源:路路发xn--668-xb9do12bcke net
) B2 ^% U4 c4 q# I0 B1 {( `% }' f% S& J, e" S1 B: K' v, R4 Z3 m! ]
(二)+ P8 k  D+ F3 ?. `4 B# \% {  P: A6 Q
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123456789….这样的楼梯缆为什么行不通呢? 是因为注码最终回不到原点。, |0 {/ ~5 f' w$ D& _: }# u( A" p
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楼梯缆每一层级上升与下降的概率速度都是50:50+ q9 ~, b" {) u: M/ W5 O- L  l+ Q
/ J# s: e& E2 \/ u! a
如果我们的注码上升的速度是7/16 而下降的速度是9/16% d' s% w3 O; }/ p4 K; _$ ^

1 A5 j9 F2 H) H这样最终是可以回到原点获利的。
4 X0 Y! u) u) C% ?" F$ o/ [, s0 K7 ~8 t, P# [1 u( v1 I' U
但是以这样的方式去设计注码,注码仍然上升得很快。以至很快超过限红。
2 M/ L. l9 O' Y1 N6 e2 ~: L2 h, J# U. ]. f3 \$ Y
更进一步,我们设计出了更好的注码。' `1 q7 o' Q4 q8 X8 }: @% E

, G3 {% G- p$ T/ X* Q/ P/ ^第一层赢两个基本码(发生的概率是9/16)–升级到第二层赢两个基本码(概率9/16)–再回到第一层赢两个基本码(概率9/16)
  Z3 }" J" v0 k  M
, C1 D, R. @% K+ ~1 |# Y也即是:第一层赢–第二层赢–第一层赢
3 y0 N' w  }+ J2 O0 R7 u! d3 _6 |$ m7 m( |- Q( D; q/ }' |8 t
(注码以9/16-7/16的速度从左向右流动)# e8 [; T! b& ^" h0 V/ U

" \7 r1 g3 x! [3 ]' @* R第一层赢–第二层赢–第三层赢–第二层赢–第一层赢/ X# s6 l0 A. T
1 P. e( X* P9 Z/ X( @* H! r) T
(注码以9/16-7/16的速度从左向右流动): n8 |* ?& }1 |; ~- a# ]
4 {% H9 R$ {4 A1 O/ {' u' C
第一层赢–第二层赢–第三层赢–第四层赢–第三层赢–第二层赢–第一层赢
# c! c7 T+ ^0 ]
9 U9 X- Y! s( }8 M- H(注码以9/16-7/16的速度从左向右流动)) o, T) `) k. ?2 v7 H( O: K# L
( e8 b/ v8 m# e% v2 s2 W2 O
第一层赢–第二层赢–第三层赢–第N-1层赢–第N层赢–第N-1层赢–第三层赢–第二层赢–第一层赢
8 ?8 a" O# F$ ^. e6 u* Z$ W. T/ o% L/ }; h# _) }6 }0 [. Y
(注码以9/16-7/16的速度从左向右流动)1 V( u: P/ w% u. G3 G# _- E
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(三)3 y: ]  H  C' W4 F9 l1 O& D
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N值的大小,决定了振幅的大小。" A* d/ i/ l" W- ]
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如果有足够雄厚的资金,这方式本身就可以实现必胜了。
  B; y% A0 `  X

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参与人数 1贡献值 +3 收起 理由
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avatar
理论的话也是要学习一下才行的了
avatar
只谈理论不谈经验是正确的
avatar
47#
有了好的理论,玩起来少走弯路啦
avatar
这个经验也是要多玩才有的了
avatar
还真的是啊,也是要看清楚的呀
avatar
理论虽然看起来很牛逼,或许我还是不行
avatar
必胜法非常给力哦,发达了吗?
avatar
这个理论或许是大伙实现的成果。
avatar
41#
负追是一种回本的办法了,有时间的话应该尝试尝试。
avatar
40#
这个理论打法是需要向这个朋友多学习一下的。
avatar
39#
楼主估计也是一个理论很内行的玩家,谢谢你的分享。
avatar
负追也是厉害的选项了的呢。
avatar
基础理论也是要看看的了哦
avatar
36#
什么必胜法必赢法的,统统走开我只相信我自己
avatar
倘若世界有必胜法那么如今可能会有很多富人
avatar
别太单纯哦世界上哪里有必胜法的啊!
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