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通过我几个月来对珠路理论的研究,% H* u' t0 x* R& c m2 ^& {' Q
$ |1 W H$ d& Z: S k
发现了一个有趣的现象,. k# T/ p. G, J s2 `
每一条大路,/ K: L* o L! v& \
按2珠路排列,有2种不同的路数0 n+ I8 e$ L- j$ s4 x0 P( b
按3主路排列,有3种不同的路数, j- v: q7 J- J. j0 s- C& ?
按4珠路排列,有4种不同的路数
! d: N: C) ?$ W4 ^. p按N珠路排列,有N种不同的路数。
/ w2 f7 O z& @3 M7 M. L什么意思呢,可能大家一时不清楚,; R- @6 e P8 e# j. p" H/ I2 v ]
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。- K$ Y f( \9 V& H
假设大路开这样的路:
+ u" z3 ?& L: `/ {3 K2 o. q2 Z: _$ E12121212121212121212121212121212& j3 }) f9 W$ B" X
够极端了吧
) p, \( Z0 e9 |: O' J按2珠路,就是BPBPBPBPBP.....1 l Y' ^0 s; O: B6 _# p
如果我们去掉第一口,就会出现完全相反的结果:; {; h5 H. v# C9 |3 r3 Z- L- |/ _
21212121212121212121212121212121
! H- f7 q+ s3 ?6 W( B& v变成了PBPBPBPBPB.......
4 a6 l- g7 y; L5 B; N4 r& {如果我们再去掉一口,又返回第一种情况了。& h$ p+ [; M# k& ~2 B% ?
所以每一条大路,' K- A# h4 `, G* h
按2珠路排列,有2种不同的路数。/ r0 X! ^$ A$ {+ h, {: q; c
再举一个列子:
, U- I& K- ^; {. H- ]- ]7 K0 Q大路:122122122122122122。。。, {) F! P0 Y5 v( o Z! L# i
按三珠路排列:
4 x4 l+ U/ V. ]$ {7 p3 B# K122,122,122,122,122,122。。。" S, I8 S2 A3 G6 k: k$ ]2 L5 n
去掉第一口,变成:- ~$ l& k* Y+ {9 u& Y
221,221,221,221,221,1 z {9 j0 m; G a" R; E* C
去掉前2口,变成:3 F0 m0 B- v- `: M2 n
212,212,212,212,212,2 `+ ?# |! V6 L# l5 ]+ q2 \- j
去掉3口,又返回122,122,122,了( S5 V* Z: Z# i4 [- I- ], E
所以每一条大路,; M, z0 ^$ P* N! g- J- |& y& g6 {
按3珠路排列,有3种不同的路数。4 q# ?+ ^& j& @5 Z q5 `: ]
同理:按N珠路排列,有N种不同的路数。: I. f3 a% z* ^
我提出这个的意义在于:
1 N, b! {, M) Z+ ]) ~3 l字串8
7 i' L! H3 M) H5 b( L+ J6 V0 Z9 {+ H6 ^
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。
: D3 b% W8 x2 Q; f3 O2、为三多理论提供了下注的多面性奠定基础。7 U4 z" |3 S8 `8 Q l7 @ Q
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.8 I a8 u, o. I: |
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楼主估计也是一个理论很内行的玩家,谢谢老哥的分享。 |
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我现在还是研究一下理论打法,感激楼主的分享,我也来学习 |
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