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“四二法则”是一种估算概率的方法,让你能快速计算你想要的牌出现的概率。+ J' p" U4 d* b5 A
7 N7 ]! _! {! _3 U7 f
比如:桌子上的牌是A-6-7-Q,而你的手牌是8-9。你想要再来一张5或者10来凑成顺子,但你只剩最后一轮机会。- C2 y+ V3 S7 c) w6 r4 e, N
) ]8 w6 p9 r' t2 w( Z* S严格来计算德扑概率应该这样:( n2 h( a; m. f( @+ r/ a6 h
z9 n, h+ w* i1 ^一副牌52张,去掉翻牌3张,转牌1张,手牌2张,剩下52-3-2-1=46张;
! @+ i, e7 |: p
. E8 @) h4 [! [ x9 e& ~1 C你想要的牌是4张5和4张10,共4+4=8张。( b, |$ [/ o2 X' r* g
$ j( e, O' A- U: b* U; x4 ?$ Z# D
那么此时,你在河牌中顺子的概率为:8/46=0.1739,即17%。" d' l* k1 j. s, D: S6 c
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你可能觉得这样计算会比较麻烦,于是就有了四二法则,即:你想要的牌有4+4=8张,
j/ k' `6 L# |
' b3 t; g" G8 u& t8 r" Z只剩最后一轮机会,所以让8*2=16,即你有约16%的机会中顺子,与上述17%基本近似。
$ A9 D! t3 A7 J8 x+ p& I( h
. h8 Y8 K1 k+ o! @: j这是四二法则中的“二”。6 a: g9 F& P3 |5 j
+ a( E- }4 A0 c+ x9 V' F, O- e当然,如果你还有两轮机会的话,即河牌圈与转牌圈,情况是这样的。6 i) _8 X2 m5 \7 q9 f, E$ P4 o0 T
& W+ v) \ u3 a7 N比如桌子上翻牌为A-6-7,你的手牌依旧是8,9。8 q5 G- P+ Q# i2 U$ l
6 u& q6 B8 L, ]9 A; S8 `% ]; u不一样的是,你有两轮机会来等5或者10,共8张想要的牌
2 T9 l. j8 L' n. E% P. ~, y8 U
" t' p% h$ ^/ }) r- q那么两轮内你中顺子的概率为:
% K+ f/ {3 s% R7 e" P9 M
4 B( o+ {7 a4 N1-(47-8)/47*(46-8)/46=0.3145,即约为31%。/ |3 h8 y, V$ p2 J V. u6 c" D& Q
6 q e( W/ J6 c. E9 N! S% c$ B4 K
那么利用四二法则,8*4=32,即你约有32%的机会中顺子,是不是跟理论值也很接近。
( |3 d) a5 R2 w$ i4 v; N: t6 u: s0 [. Q
这就是四二法则中的“四”。$ d$ A' M' P0 m& Z2 s" G
0 ^ V! ]1 r$ T& G+ G) O总之就是,先想好自己想要的牌的张数,然后,还有两轮机会就乘4,还有一轮机会就乘2,得到的就是你想要的牌接下来会出现的概率。接着,根据真人德扑圈的游戏玩家以及战况来决定接下来该怎么办。利用好四二法则,可以帮你快速估算概率。
- U$ Z- S, D; w. b+ P% X; v& m* b) Q% @# Y
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我现在还是研究一下理论打法,感谢楼主的分享,我也来学习 |
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方法最后一段话觉得是实用的,但是在我面前就难以实现,毕竟运程太差了。 |
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