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[lastpost] => 2778182 【吉祥坊】11月2日投注流水2200元 1762061061 22301
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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。3 x: d( c: n2 T7 b% _0 W
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一般来说," N9 x3 i2 d4 s& c0 z+ u& j2 U
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二连赢的概率是25%
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三连赢的概率是12.5%
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四连赢的概率是6.25%
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……
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: }/ }" {$ k2 w- r% d* F十连赢的概率是0.09765625%
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3 y: n' }9 ^: u B这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。. w9 J' `0 s4 _
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百家乐的真实概率含义是:3 S8 g0 H( h2 X1 O$ |4 M$ |2 w
* Z' f3 n# k. z' w假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球# @2 z0 ^4 x3 o1 D: X) Q t
% Q1 m9 R: b! Y. G$ @1 M1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。( u- _3 w, x; M* M
" B' L( B: C! a' p% Y& T" A+ X你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。) i- T3 G- G) `" m5 Z% X
: ~5 y) N7 m: ]你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。0 X8 U i* U. p) ^. A0 [/ h
# T7 w k( l# ]- C; l8 W& z' v另外一个说法是,3 b' s! v7 M- |' r" Q
3 P2 ?7 a+ y5 Q$ P4 Q1 {4 @1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。1 ~1 r- ]# m/ Q6 H! r
$ d9 J% v4 a& T5 ]9 P! O再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。* ]( ~- J1 e: | }& l7 `. j
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。- z! s% Y r$ _! p9 y0 R
: g0 u' l; @5 \% n- b* f4 O: b; w- P举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化# Z( x5 g9 V, ], _2 ^
) i! ]& S2 J- B2 J第三,凯利公式的问题在于:形而上学。# M( V3 ~% [+ I4 e
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首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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事实上,你玩的时候,基本上每次都能打到。
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因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。& q: L3 G b% @' u9 L6 [
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