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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O
( K3 E1 l+ [& e0 T( b+ d9 j
6 `. v# G! O; e( q/ P$ V' a' y" v$ j发现了一个有趣的现象，
) y! S3 Z3 n; b, y3 S) o每一条大路，% Y2 z& [; s$ N3 {* I
按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
4 N, x$ J% u8 G" `. @6 b按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z, Y' n3 ~7 N# x
按4珠路排列，有4种不同的路数
2 b% u0 K3 P* M! V, A% Z* b) X7 r按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
% ~# B- r) `+ G+ o什么意思呢，可能大家一时不清楚，
Q" B1 Y9 f; U! e8 \: K: `我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l; e2 E& t: |7 h2 y, q6 I4 S7 s0 i
假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
8 n+ O% O- Q: D. g12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h, Y% A- |# o: ^2 t- u% K% D+ G6 W
够极端了吧 g4 p9 T0 a+ W
按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F5 L" ~- U8 Y. P5 h
如果我们去掉第一口，就会出现完全相反的结果：5 R& t' A5 q6 V- D( v
21212121212121212121212121212121
+ q9 n# S* I( v0 W- X; p$ h0 P9 ~变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C% t4 M+ ], k' S
如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
# J* q B" B; T6 n所以每一条大路，! R6 V# q$ h. c; z% O
- K/ S# b& W: r0 N. Z按2珠路排列，有2种不同的路数。4 L/ S M0 A1 L2 G
再举一个列子：' S4 k5 Q6 _* u! I, J6 X4 A2 e4 H
大路：122122122122122122。。。# Z2 g: C6 j# _9 x2 l; i- d
按三珠路排列：
5 A$ b9 x: ]8 B6 g- Y122，122，122，122，122，122。。。* j2 L+ j- G1 M! Q
去掉第一口，变成：6 G2 V! \" L' c" k: d, |* [ U4 g. s8 q
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M
1 _( U, \. c# U0 o0 ^去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W; m) |' C+ G6 i( e
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `
t' s1 U4 K8 n% z7 \! M' L去掉3口，又返回122，122，122，了
; D5 {0 Q/ @( u" z9 y2 x所以每一条大路，. a ~( v. ~+ ]3 K0 b) X3 g8 v
按3珠路排列，有3种不同的路数。
+ L0 e {4 p/ E同理：按N珠路排列，有N种不同的路数。
g, e% M& Y# Q, r6 I我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
& t+ [" V6 ^* S+ f6 a3 u# Z! g字串83 L: R) G1 V- s2 Y+ Y6 b* t( I: z' t
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @( p+ O# r1 A! q% T
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |% D. i: A9 d( ^' D' M5 b- N
2、为三多理论提供了下注的多面性奠定基础。# y' Z% I4 m7 w1 o; a. i5 g
3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.. }- o: c% {% ]' ^# |0 @
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