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[lastpost] => 2760735 【YZ】8月26日投注流水75095元 1756454320 rainwang
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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。, q9 W* }6 w3 {" E
, Z# ` K, F9 n' ]+ ]一般来说,
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二连赢的概率是25%' R3 Z) H* g7 `" \+ v1 U2 L' Y7 Z
0 P8 M r/ w; @! u! Q0 j! ^三连赢的概率是12.5%
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四连赢的概率是6.25%& E/ O. F- k) W2 i. W
0 Y- d; b, V* [……
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十连赢的概率是0.09765625%. r9 }6 a3 x# q) u+ e
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这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。
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百家乐的真实概率含义是:* r! A8 @4 K0 X" x( a
, [" M. _& T, {3 z( R N% l假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球
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5 t5 G, M6 y) _; j9 Y3 I1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。/ D$ X1 I7 j, n
6 V2 @2 Q1 ~, r; ]3 G2 e你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。0 {" {2 W) j! B# y0 I9 Q4 C
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你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。7 Z0 l0 j! Z( Q- |! V) ^
4 P. {% K1 k$ [! J4 f" }另外一个说法是,
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1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。
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5 L: N5 i( @1 S c) `9 R2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。
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9 {3 j& t2 f; @5 Y再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。% M; I( Y0 P# K' c" F y: g6 C! _
5 k/ a; g j1 c& A% d$ I4 G2 w- L平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。( D) w( Z! c) z) E3 j
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对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
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举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。0 y d( t* l, ]$ Y( ]
- X: q0 P' g9 `. B第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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! J& K$ \/ ?" N- h3 s- R/ y/ s第三,凯利公式的问题在于:形而上学。9 s, ^7 @% H# O* ?4 C7 p7 B
7 B) r9 g! }: j* n7 M1 G首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。
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事实上,你玩的时候,基本上每次都能打到。
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3 C6 P. ?' z9 s7 L4 c' b2 V# y5 f因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。# Y3 u" d' `( u7 D. f; A
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