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[lastpost] => 2787652 【星宝】12月8日投注流水10230元 1765195609 22301
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很多玩家都在苦苦追寻百家乐的连赢玩法,但是对于连赢的认识并不深入。其实百家乐连赢概率和连赢策略是相通,只要摸清了游戏特点,才能找到制胜方法。$ Q" z! f: ^8 a& M" K+ _/ O
& X' w& j' g7 n: {一般来说,
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+ } i% f' n' h' Q" I1 `& N) G二连赢的概率是25%
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三连赢的概率是12.5%
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四连赢的概率是6.25%! Q% I7 `+ ?6 W; e% B/ N8 a
' G7 Z/ h" {7 E……
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十连赢的概率是0.09765625%
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2 Q8 {" Z0 U$ b9 D这些概率值是所谓的相对概率,也就是二连赢25%的意思是只连续抛硬币4次之后,会有四种结果,二连赢就是其中的1种,所以他的概率是25%,同样的十连赢的概率也是基于1024次的10次抛硬币的结果组成。/ l$ D" A+ T5 ]1 }
4 p# l( \. N+ v/ y/ c# ~百家乐的真实概率含义是:
2 ~% p) J) W3 b4 p) h. {
5 m% R4 Z) R4 x* e- o假定一个口袋里有很多个球,其中有1号,2号,3号,4号,5号,6号,7号,8号,9号,10号球/ L0 G: O/ g a5 I$ c3 `. o+ s
5 O9 X) E9 [! a1 X0 O8 e. u1 ]8 T1号球有512个,2号256个,3号128个,4号64个,5号32个,6号16个,7号8个,8号4个,9号2个,10号1个。# Z0 e) R! L: y
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你要做的就是在这么多球里面每次摸一个球,然后放回去,再重新摸。如果你第一次摸到10号球,第一次一样也可以再摸到10次。# X# X$ x4 o$ z$ f7 {1 O5 k
3 N1 M# a# t/ [; ^/ Z$ b3 A你每一次摸到的任何一个球的概率都是存在的,除非你摸无限次,才能接近之前提到的概率。概率在个体和短期内是无效的。
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: J/ [% M4 j+ [ ^2 Q( ~另外一个说法是,( C A, X* H% v3 X
" N; x* k% m- S: ]% `1、百家乐不是每次摸一个球,然后放回去,再重新摸,而是每次摸一个球,不放回去,再剩下的球里重新摸。, p& ?" i, e6 d6 }. a' Q4 N
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2、概率在个体和短期内是有效的,牌入盒后出闲的概率是:49.32%,但是随着发出的牌的变化,牌盒内所剩下的牌数量的减少,他的概率就会每时每刻都会变化。/ D; N! U& }; I! n0 A* S" r+ \
; h5 G# c' y, r' [4 a' p: }: |! G再把这个概率代入期望值公式,当+EV出现就下注,就会做到平均赢。# c: I* N# d2 U: u5 C8 M' T8 s
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平均赢只是长期而言会赢,短期也可能会被震幅消灭,这时就要算标准差,再接合你获得的优势,按凯利值下注就可以做到破产风险最低,利润最大化。- Q. q0 Y( `/ i2 b# k' J7 `8 [$ X/ [
6 N0 h7 h% m) W: F
对于这样的说法,百家乐玩家的解释是,首先,百家乐肯定是每次摸一球个放进去,只是袋子里的球和你的数学模型一定要配合。
$ h7 F# I" R- R( z c) z2 H7 p, h1 j6 i8 Z$ C" k& q5 d" N
举个例子,如果你是打庄闲的,袋子里永远只有两个球,每次摸完一个之后要放回去,然后再摸。这个概念是不容置疑的。3 n; v3 A! Z& |: x2 |4 ^
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第二,因为大数法则和算牌对百家乐的无效性,牌盒内所剩下多少牌,对庄闲的比例不会发生任何的变化
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第三,凯利公式的问题在于:形而上学。
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2 }2 l1 X4 B$ K, i+ C( V9 l& F首先主观假设了一个不成立的底部,玩久了一定会遇到被爆仓的概念,当然任何一种模型都会有爆仓的可能,只是单纯的凯利更容易爆仓而已。研究的方向是多维+赢进补偿,玩过Diablo3就知道在Mp8的难度下,打到钥匙的可能性是80%。+ K- b! X* k" E
' [! `9 ~" v: [. o事实上,你玩的时候,基本上每次都能打到。
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3 L4 O2 C! F* L. I2 z2 x因此,百家乐连赢概率和连赢策略,对于不同的玩家有不同的理解,如何找到适合于自己的玩法和制胜之道,是每个玩家都需要积累实战经验去摸索的。
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