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[打法交流] 百家乐珠路理论技巧(转)
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通过我几个月来对珠路理论的研究,5 R+ y* d$ ?  k6 I7 G/ O
9 r5 a, A2 {5 F/ x$ ~3 @2 g2 w+ }5 V5 O# ?: E- _% ~* ?
发现了一个有趣的现象,) p( K7 t, z3 B3 K2 l8 g5 h
每一条大路,
2 ?+ ^5 N# l/ [3 w按2珠路排列,有2种不同的路数1 _% l2 j  Y8 @" u) {# f1 ]6 y2 O$ S3 d
按3主路排列,有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
# |$ F& T# s* ~" ~) v) D8 {, a按4珠路排列,有4种不同的路数
& N5 q/ G9 w4 f- l按N珠路排列,有N种不同的路数。: n1 f3 R9 @  p% ]* C* W* L8 k# {1 n
什么意思呢,可能大家一时不清楚," E: S5 f$ Q' m" c
我举一个例子,假设 B= 1 , P=2,T暂且忽略吧。7 f# f3 c1 ~2 l
8 E9 L: W4 g+ O/ l% p假设大路开这样的路:! z  ~0 G3 v. K' o5 A4 ]" }5 w# u( ^* O% ]% a4 K, y0 K& Q, A( z
12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h
) s/ A0 u" W; w够极端了吧
6 Y2 {) V  t) y& T5 C按2珠路,就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F
: l2 J, U* m/ l+ s% A( b) ]" F如果我们去掉第一口,就会出现完全相反的结果:2 y/ i$ \3 n% q7 K, ^% ^: W% H, t1 G9 ?2 @
21212121212121212121212121212121
( e! u, N, e: S  ?变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
" y5 w% A/ K$ T+ U如果我们再去掉一口,又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
, a; I, b% l) B& `2 B3 e所以每一条大路,! R6 V# q$ h. c; z% O
' a! n% o  s0 Y% S按2珠路排列,有2种不同的路数。; n1 ~) {: }: O  J+ q
再举一个列子:$ |; w$ s+ N$ q; M  Z7 Z
大路:122122122122122122。。。! x; Y  Q7 S1 g. X
按三珠路排列:% B% I- }. o7 q7 ]" H
122,122,122,122,122,122。。。: D" n# q0 i1 c7 e
去掉第一口,变成:6 G2 V! \" L' c" k: d
' h' f$ W; Y5 X9 N221,221,221,221,221,+ R$ P2 d/ f7 Z, P5 M
: f5 \- C8 }& C去掉前2口,变成:3 v1 q) z( ?2 f! }) U/ W2 b% ]4 S% e& s8 q
212,212,212,212,212,: y& l, B; I6 e- m. J# c) `! j9 p) v* l) H9 G# _; E+ G
去掉3口,又返回122,122,122,了
4 O6 L9 V" T2 x所以每一条大路,' v9 q2 ~: x, J# j
按3珠路排列,有3种不同的路数。' ~' y# [4 j+ B  C/ l
同理:按N珠路排列,有N种不同的路数。
. ]0 j- i( x+ H6 h/ Y我提出这个的意义在于:" v) X/ h3 }* D1 {5 J! a1 s. O
) \  T/ K# ?! v% O/ b3 z" b7 g0 }字串83 L: R) G1 V- s2 Y+ Y
$ f% i# Z  N* [. s# S" p- p, d3 [6 U. s5 J' [0 {1 A" m' k( @2 O$ r9 C; {8 }1 A* |) g7 d7 Q
1、每靴的第一口为起点来编排二三珠路,与第2口,第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |
7 p( \; m  i7 \: b8 E2 p/ i2、为三多理论提供了下注的多面性奠定基础。- c8 H& B* I4 o+ \2 c0 N
3、某一靴牌,按第一口开始的珠路可能是 烂路,按第2口,第3口开始的珠路可能是 上上路.& N& p" V# h3 v" n0 q' O7 I. L

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