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[lastpost] => 2759344 【YZ】8月23日投注流水120645元 1756039456 天策-瑶娥
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一、百家樂常见的错误
$ G; n4 S3 K+ J' v: @0 i* n* o0 S0 r
7 G8 |9 T7 W( ~3 E+ u9 I/ o3的搭配机率是1/8,如果见持续3个不异的搭配,例如BBPBBPBBP之后用3式缆反买BBP(即PPB),中一口的成功机率是否1/8x/1/8x1/8x1/8=1/4096答案是否认的。由于持续3个不异搭配已经实际呈现,等于4096个搭配之中有4096–8=4088个搭配不成能呈现,只剩低余下的8个搭配可以呈现,所以胜的机遇率仍旧是7/8。现详细列出他们以便利理解:: G8 |4 ?+ C9 B7 j8 z
Y4 { q- A+ `
1、BBP,BBP,BBP,BBB; a+ N4 c" ~* L0 b
2、BBP,BBP,BBP,BBP
7 N# i/ V9 z# q8 q3、BBP,BBP,BBP,BPB
) n1 e% t, _' C- L. p/ O4、BBP,BBP,BBP,BPP- b$ F6 Z) B( [4 j( i2 G3 Q2 _6 M
5、BBP,BBP,BBP,PPP
$ C6 g& X7 M) J6、BBP,BBP,BBP,PPB3 B5 m4 u& l* S* w, W
7、BBP,BBP,BBP,PBP
% G `9 q6 X! l/ M8、BBP,BBP,BBP,PBB
6 l. I+ u8 ]- j- s5 F: F' U" |# Q& \ d
所以无论是什么搭配,当它已经实际呈现,它的概率必定是1。已经实际呈现的BBPBBPBBP概率是1,用3式缆买反的整体胜率依然是7/8。
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. z. |% ?4 t/ D+ ]2 M, m二、2式缆赌N搭配的错误有一个很自然的想法,之前开了例如BBBPB,跟着反买它即PPPBP去赢1个码,机遇率是1/32,死穴是反复的BBBPB。+ ]' ^9 a R: v% }; m
: G4 n' u. M/ e8 E7 `. |6 e为了节流金钱,好自然想到如果输了1口或2口才追,一来可以增加取胜机遇,二来可以节流金钱,所以便发生“同买分歧,分歧买同”的心理和策略。例如:见BBBPB,再见B,可能会认为如果买了第一口已经输了,余下四口用4式缆博赢一口的机遇会大一些;又或者等已出了二口BB才用3式缆博赢一口的机遇会大一些。现实上,这个策略是按比例裁减了一些胜及负的搭配来换取低成本:只见B才下注,便会错过8个BXXXX及8个PXXXX的搭配;同样只见BB才下注,便会错过12个BBXXX及12个PPXXX的搭配;所以这个策略亦没有提高风险回报比率,它的取胜机率完全由运用的式缆来决议,即2式缆=3/43式缆=7/84式缆=15/16。! I( V& O2 U6 O5 B
三、结论+ V w; F T, [% M5 C
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无论等任何模式下注,如,PP后买B(拐弯法);PPBP后买P连;PPBPPPBP后买P不连完全没有影响50%定理。
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