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[lastpost] => 2759344 【YZ】8月23日投注流水120645元 1756039456 天策-瑶娥
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6 A @0 d* ]- g: O一、百家樂常见的错误
$ m' @$ Z. A; q2 D2 M+ R& K
G6 b* r# c V9 ?% w+ V$ [, b3的搭配机率是1/8，如果见持续3个不异的搭配，例如BBPBBPBBP之后用3式缆反买BBP（即PPB），中一口的成功机率是否1/8x/1/8x1/8x1/8=1/4096答案是否认的。由于持续3个不异搭配已经实际呈现，等于4096个搭配之中有4096–8=4088个搭配不成能呈现，只剩低余下的8个搭配可以呈现，所以胜的机遇率仍旧是7/8。现详细列出他们以便利理解：9 X! O1 ~8 i- Q7 I
1 m1 ]8 D& H+ e& k( i2 r, K1、BBP，BBP，BBP，BBB
$ s4 o% l6 J7 D( S2、BBP，BBP，BBP，BBP
, f. H( @, p8 e! B9 B+ V3、BBP，BBP，BBP，BPB. i1 G4 Q9 K3 g# A/ s/ P/ K
4、BBP，BBP，BBP，BPP" p3 c& v0 T0 ~' w( F# ~) I- p
5、BBP，BBP，BBP，PPP2 q4 N+ w& }% J! t9 _
6、BBP，BBP，BBP，PPB
2 J5 o% f8 ?! V/ m5 X. L% D7、BBP，BBP，BBP，PBP
, B+ y) H% ?7 P7 X) Z- w8、BBP，BBP，BBP，PBB3 d2 J2 [4 ]9 U' p5 F0 Y/ E
) }1 D& C- Q4 K所以无论是什么搭配，当它已经实际呈现，它的概率必定是1。已经实际呈现的BBPBBPBBP概率是1，用3式缆买反的整体胜率依然是7/8。
4 Y) X3 J! G! R) L8 n [/ G; f" F3 a' y6 o* e
二、2式缆赌N搭配的错误有一个很自然的想法，之前开了例如BBBPB，跟着反买它即PPPBP去赢1个码,机遇率是1/32，死穴是反复的BBBPB。
( g9 H6 \8 K8 C# d; O N, s" N u1 _
! F( R k3 U6 }$ a+ E为了节流金钱，好自然想到如果输了1口或2口才追，一来可以增加取胜机遇，二来可以节流金钱，所以便发生“同买分歧，分歧买同”的心理和策略。例如:见BBBPB，再见B，可能会认为如果买了第一口已经输了，余下四口用4式缆博赢一口的机遇会大一些；又或者等已出了二口BB才用3式缆博赢一口的机遇会大一些。现实上，这个策略是按比例裁减了一些胜及负的搭配来换取低成本:只见B才下注，便会错过8个BXXXX及8个PXXXX的搭配；同样只见BB才下注，便会错过12个BBXXX及12个PPXXX的搭配；所以这个策略亦没有提高风险回报比率，它的取胜机率完全由运用的式缆来决议，即2式缆=3/43式缆=7/84式缆=15/16。
. o) [# d+ Q" c2 o" Z三、结论; @7 n0 d0 T) \& D
+ n' b2 u) V! h; x5 M无论等任何模式下注，如，PP后买B（拐弯法）；PPBP后买P连；PPBPPPBP后买P不连完全没有影响50%定理。) J8 b3 C( t- N
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