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通过我几个月来对珠路理论的研究，5 R+ y* d$ ? k6 I7 G/ O* w, | L' b( [+ n) Z- I
* l: c: F0 @9 V5 e0 z发现了一个有趣的现象，# J, a% F6 M0 Q2 I% _: o
每一条大路，
& V% d3 L6 y. T+ Z4 j. x" d按2珠路排列，有2种不同的路数1 _% l2 j Y8 @" u) {# f
. e% A4 p; v/ R* z按3主路排列，有3种不同的路数& n( |2 F1 f; ?, q' L3 A: Z4 z
, j+ |8 Y, w" Q e/ P, u( I按4珠路排列，有4种不同的路数' `0 \7 ~; S9 I6 ?9 m5 h4 c
按N珠路排列，有N种不同的路数。: n1 f3 R9 @ p% ]* C
: a! Y# n( m$ o什么意思呢，可能大家一时不清楚，
9 D7 o. \+ v" l3 \4 c& [ l/ f我举一个例子，假设 B= 1 ， P=2，T暂且忽略吧。7 f# f3 c1 ~2 l
N E! w! a# d/ w* [8 A" h! W假设大路开这样的路：! z ~0 G3 v. K' o5 A4 ]" }5 w# u
0 h; \, U: s# j1 d2 }12121212121212121212121212121212, j0 j; e6 p* q3 Q5 h f6 z; a$ }9 C5 {5 I- T, N
够极端了吧
) q; l: u; S* E按2珠路，就是BPBPBPBPBP....., m8 f) O! x+ S9 L2 x) F) S# i$ P( |* U+ w$ b
如果我们去掉第一口，就会出现完全相反的结果：
3 m& N, V# r4 U @% S21212121212121212121212121212121
$ \4 \* o9 g8 g0 y( C1 f8 C变成了PBPBPBPBPB.......1 u5 g6 c6 F/ L4 g! f7 Z# E+ C
R! U% ]. v- x; \' v5 Q如果我们再去掉一口，又返回第一种情况了。! [( g, L- u! O3 @# G4 D) O
8 T7 Y; H# A) a% ?) b4 X4 h所以每一条大路，! R6 V# q$ h. c; z% O
5 D( D! F" b, W' M9 M' f按2珠路排列，有2种不同的路数。2 ], t, w* D1 f3 H6 `0 K$ U3 u
再举一个列子：
+ Q6 n3 s( W" ~+ D) G, f Z大路：122122122122122122。。。
% W L8 u4 q4 P- R9 `按三珠路排列：' P9 a" P, T- k# Y
122，122，122，122，122，122。。。' O) t% J5 Y3 R! i
去掉第一口，变成：6 G2 V! \" L' c" k: d; g! h6 o# f3 @5 y; e5 t5 X0 O
221，221，221，221，221，+ R$ P2 d/ f7 Z, P5 M. i6 G! R5 D; M& M# A
去掉前2口，变成：3 v1 q) z( ?2 f! }) U/ W5 H: ?1 \2 C0 x4 O' M0 U- D
212，212，212，212，212，: y& l, B; I6 e- m. J# c) `2 M$ T; B2 q% P% e
去掉3口，又返回122，122，122，了
8 X" W- u, o& `所以每一条大路，
% ]+ I5 W/ L' N: V按3珠路排列，有3种不同的路数。1 f) v: W) Z ^4 O) B& Z
同理：按N珠路排列，有N种不同的路数。) j' |8 o+ u! k* d! `
我提出这个的意义在于：" v) X/ h3 }* D1 {5 J! a1 s. O
4 A2 [$ B9 J+ e, ?字串83 L: R) G1 V- s2 Y+ Y& C4 P: q' q1 }; K' \: ^
- p, d3 [6 U. s5 J' [0 {1 A" m' k( @7 }! q1 @# U# `
1、每靴的第一口为起点来编排二三珠路，与第2口，第3口开始的排列是不同的结果。2 g: X/ W# h7 N" o7 |9 l* |! a! D+ A( o0 j
2、为三多理论提供了下注的多面性奠定基础。
/ J2 f s. \ V i0 E! e) f z3、某一靴牌，按第一口开始的珠路可能是 烂路，按第2口，第3口开始的珠路可能是 上上路.. o T- \) h1 [3 s7 Y7 B+ x3 R. y& x
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